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100% VERIFIED 2016/2017 WAEC MATHEMATICS THEORY AND OBJ QUESTIONS AND ANSWERS

Poster: alexical | Date: 8:02pm, 19th Apr 2016. | Views: 1044 | 1 Replies
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alexical . Jalingo, Taraba
8:02pm, 19th Apr 2016.
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MATHS ANSWERS:
6a)
Sn=n/2(2a+(n-1)d)
A=1, d=2, n=n Sn=n/2(2*1+(n-1)2)
N/2(2+2,-2) =n/2*2=n^2
==========================
(No.7a)
x-2/4 :x+2/2x
Cross multiply
2x(x-2)=4(x+2)
Opening the bracket
2x^2-4x = 4x+8
Collect like terms together
2x^2-4x-4x-8=0
2x^2-8x-8=0
Solving with completing the square method
2x^2-8x=8
Divide through with the coefficient of x^2
2x^2/2-8x/2=8/2
X^2-4x=4
Half of coefficient of x
(-4 x 1/2)^2 = (-2)^2
X^2-4x+(-2)^2=4+(-2)^2
X^2-4x+(-2)^2=4+4
(x-2)^2=8
X-2:square root 8
X=2 + or - squar root 8
X=2+ square root 8 or x=2- square root 8
X=2+2.828=4.828
X=2-2.828= -0.828
X=4:83 or - 0.83.
============================
13a)
(x1,y1) =(2,-3) for 2x + y =6 y=-2x +6
compare y = mx +6 m2 = -2
for parallel lines, m1=m2
: y-y1/x-x1 = m
y--3/x-2 =-2/1
y + 3 = -2(x -2)
y + 3 = -2x + 4
y = -2x + 4 -3
y = -2x + 1
================
9a)
x 62 63 64 65 66 67 68
tally 1 iiiii iiiii iiiii ii iiii iiii iiii iiiii iiiii iiiii i ii
freq 1 5 12 14 10 6 2 total = 50
fx 62 315 768 910 660 402 136 tot = 3253
x -x - - 3. 06 - 2. 06 -1 . 06 0. 06 0. 94 1. 94
2. 94
( x -x -) 9 . 3636 4. 2436 1. 1236 0. 0036 0.
8836
3. 7636 8. 6436
f ( x -x ) 2 9. 3636 21. 218 13. 4832 0. 0504 8.
836
22. 5816 17. 2872 tot = 92 . 82
9bi) mean = EFX /EF = 3253 /50 =65. 06
bii ) Standard deviation = Square root of EF( x
-
x ) 2/Ef
= Square root of 92. 82 /50
= square root of 1. 8564
= 1 . 36
============
=========
11a)
3p+4q/3p-4q* 2/1 find p:q
1(rp+4q)= 2(3p-4q)
3p+4q=6p-8q
Collect like terms
3p-6p=-8q-4q
-3p=-12q
Ther4 p:q = -3p/-3=-12q/-3
P=4q, p=4, q=1
P:q= 4:1
11b)
Ts=pq-(2+2)
Ts=pq-4
Circumference of Ts= 2pie(TS)
11bi.
Ts=pq-(2+2)
Ts=pq-4
Circumference of Ts= 2pie(TS)
=2pie(pq-4)
Perimeter=pq+4+4+2+2+2pie(pq-4)
34=pq+12+2pie(pq-4)
34-12=pq+2piePQ-8pie
22=PQ(1+2pie)-8pie
22=pq(1(2*22/7)-8*22/7
22=pq(1+44/7)-176/7
22=PQ(7+44/7)-176/7
22+176/7 =pq(51/7)
154+176/7=Pq(51/7)
330/7=pq(51/7)
330/51=pq
Pq=6.4706
11bii.
TS=PQ-4=6.4706-4=2.4706m
Area of semi circle TS=pieD
=7.7626m^2
Area of rectangle PqRU=|pu|*|Pq|
4**6.4706=25.8824
Area of the cross section=area of rectangle-
area
of semi
circle
=25.8824-7.7626
=18.1198m^2
================================

8a)
<KGF = 110
2x = r = y
if <KGF = 110, <MGH = 180 - 110
<MGH =70degree
<HMG = Y
<MHG = 180 - Y - 70
<MHG = 110 - Y
<LHJ = 180 -(110 -Y)
=180 - 110 + Y = 70 + Y
nOW : X + r + 70 + y = 180
2x = r + - y
if 2x = r
x = r/2 =y
:x + 2x + 70 + 2x = 180
5x = 180 -70 = 110
x = 110/5 = 22degree
================================

( 3b)
h=7cm
T =462cm ^2
T =pie sqr + 2 pie rH
462= pie( r ^2 +2* 7*r )
462/3 . 142
=r sqr = =14r
r sqr + 14r =147
r sqr + 14r - 147= 0
r = 14 +-( ( sqr ( 14))- 4* 1*147 ) /2* 1
r =-( 14 +- ( 196- 4))/2
r =( -14 +_ 12) /2
r =( -14 +12) /2 or
r =2/2
=1cm
==================================
( 4a)
Pr ( 3)= x /total
total= 25+30 +x +28 +40+32
=155 +x
0. 225 =x /155 + x
=34. 875+ 0. 225 x =x
x -0 . 225 x =34. 875
=0. 775x = 34. 875 degree
x =34 . 875 /0. 775
=45
( 4b)
Pr ( even)= 30+ 28+40 +32
=90
Pr ( even)= 90/200 =9/20
Pr ( prime no )= 25=30 +45+ 40
=140
Pr ( prime no )= 140/200 =14 /20
Pr ( even or prime)= 9/20 + 14/20
===========================



The Objectives
MATHS OBJ:
1-10: DCBCABBADA
11-20: CCBDABABBA
21-30: CACCDDDACC
31-40: BCDCDCBADA
41-50: ABACBBDADD

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